But strangely these "dudes" have sum properties that are so similar that one can put them into a set which is a subset of "fake" individuals. Mathematically
P(dudes)
now dudes group/set follows a few axioms
a. Dudes are Dudes( which is self evident)
b. Dudes + Dude = Dude
c. Dude+ intelligent = Dude+ Frustrated Intelligent(this is a transformation matrix)
Dude Dude [ intelligent intelligent] = [ DI DI]
Dude Dude X
Here the dude is the transformation matrix and not the intelligent, In lay man terms dudes transform the intelligent guys and never vice versa.
d. Dudes always spew gibberish.
Ie. [dude]X ( any signal)= Total White noise
This is sumthing like the infinite series property.
Infinity X any finite Qnty = infinity
Hence Dude is Human equivalent of infinity
e. Dudes don’t always understand each other
Ie. Dude1 --à Dude2 doesn’t necessarily mean
Dude 2--à Dude 1
Which basically means that Dudes are not commutative
f. Dudes deny their culture even while staying inside it
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g. Dudes do not have any weight hence the total mean of Dudes is zero
ie. Sum (Dudes) = 0
Using these basic Axioms we can build a new branch of mathematics and use it to study “dudes” . Any scientific papers on the subject are welcome on this blog
2 comments:
following the same spirit of dude matics let us now have a brief session on "dude calculus"
d(dude)/dt >= 0
(once a dude, remains a dude or becomes a bigger dude)
d(k*dude)/dt >= k*d(dude)/dt
('k' dudes hanging out together would result in greater dudeness in time then when the dudes are saperated)
d2(dude)/dt2 >= 0
the rate at which the dude becomes a bigger dude is also positive.
d(dude)/d(money) >= 0
it cost's money for the dude to become bigger dude. which they become anyways.
d(dude)/d(girl) = girls^(her intelligence)
The more intelligent the girl is the more dude the dude becomes... (which in turn costs him money)
dude has no additive inverse!
dude + (-dude) = 2*dude
Therefore,
d(dude1 + or - dude2)/d(same girl) = 2*girls^(her intelligence)
(an intelligent girl takes advantage of both the dudes, irrespective of whether the dudes are friends or enemies)
integral(dude).dt = area covered by the dude roaming behind girls
integral(integral(dude)).dt.d(girl) = area covered by the dude roaming around the same girl
dude + bike = bigger dude
therefore
integral(d(dude+bike)/d(girls)).d(girl) = girl + shopping + multiplex + restaurants
a dude with bike roaming around girls, ends up as a paying driver
dude + mobile = bigger dude
basically
dude + anything = bigger dude
actually
dude +/- anything = bigger dude
wait that proves my original axiom that
d(dude)/dt >= 0
- thanks and regards,
"intelligent dude"
Pradeep ..ur work is original and intelligent . However we have to sit down and solve it on pen and paper. I have a few axioms on graph theory of dudes. will require your comments. Infact we can make a branching tree of dudes and non dudes and model a markov chain on that basis. (the memoryless property of Dudes will be an asset in this analysis)
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